The moles are literally the molar mass of a solute and has the moles of solute and solvent of this solution as the average mass percent of saccharin in the tablets is 69%.
The sulfur (S) is oxidized to sulfate ions (SO₄²⁻). All the SO₄²⁻ ions are brought about with BaCl₂ answer withinside the shape of BaSO₄ (s).
The response is as follows-
- BaCl₂ (aq) + SO₄²⁻ (aq) → BaSO₄ (s) + 2Cl⁻
- So, this shows that after 1 mol of Saccharin (C₇H₅NO₃S) is dissolved, then 1 mol of BaSO₄ is brought about.
- The quantity of moles of C₇H₅NO₃S is same to the quantity of moles of BaSO₄.
- The quantity of moles of BaSO₄ = (mass of BaSO₄ obtained) / (molecular mass of BaSO₄) = (0.5032 g) / (233.39 g/mol) = 0.0022 moles
- So, The quantity of moles of C₇H₅NO₃S = 0.0022 moles
- Mass of Saccharin (C₇H₅NO₃S) = (quantity of moles of C₇H₅NO₃S) × (molecular mass of C₇H₅NO₃S) = (0.0022 moles) × (183.18 g/mol) = 0.403 g
- The common mass percent of Saccharin (C₇H₅NO₃S) in drugs may be decided by-
- [(mass of C₇H₅NO₃S) / (mass of tablets)] × 100 % = [ (0.403 g) / (0.5894 g) ] × 100 % = 68.37 %
- 68.37n be rounded off as 69 %
- So, the common mass percent of Saccharin (C₇H₅NO₃S) in drugs is 69 %.
Read more about mass;
https://brainly.com/question/15356425
#SPJ4
