12.7 L of argon at 33°C and 735 torr are dissolved in enough water to give a final volume of 0.750 L. What is the molarity of the resulting solution 6.02 M 0.652 M 0.0644 M 0.489 M 4.95 M Con

Respuesta :

The molarity of the gas can be obtained from the parameters in the question as 0.65 M. Option B

What is the molarity?

We first have to take our minds back so that we can be able to understand what we mean by the molarity of a solution. We know that molarity has to do with the amount of the substance that can be found in the solution. In this case, we have to also know that the molarity can only be expressed in the units that we call mole per litre.

We now have to find the number of moles of the gas and this can only be obtained by the use of the ideal gas equation and that is what we are going to be able to do now in this problem.

PV = nRT

P = pressure

V = volume

n = Number of moles

R = gas constant

T = temperature

n = PV/RT

n = 0.97 * 12.7/0.082 * 306

n = 12.3/25.1

n = 0.49 moles

Molarity of the solution = Number of moles/volume

= 0.49 moles/0.750 L

= 0.65 M

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