Respuesta :
Total energy required to warm 1 kg of ice is 834.3 KJ. This is calculated using latent heat and specific heat.
We can calculate the amount of heat required to raise the temperature of 1 kg of ice from -40°C to 0 °C from the latent heat of fusion. Latent heat is the energy absorbed or released by a substance during a change in its physical state that occurs without changing its temperature.
Quantity of heat =Mass x latent heat + mass x specific heat x (final - initial temp)
Mass is 1 kg.
Final temp = 0℃
Initial temp = -40℃
Latent heat of fusion for ice = 333.55 kJ/kg
Specific heat of ice 2.090KJ/kg °C
Specific heat is the the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.
Total heat required = 2*333.55 + 2* 2.090 *(0- (-40))
=834.3 KJ
To learn more about Specific heat please visit:
https://brainly.com/question/27991746
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