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Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions.
a. n = 4¡n = 3
b. n = 5¡n = 1
c. n = 5¡n = 4
d. n = 6¡n = 5

Respuesta :

The frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions energy of the electron in the nth state is En = -2.18 x 10-18J for the n = 4¡n = 3

Therefore, when an electron transitions from nito to ng, the energy of the emitted photon is the energy of the electron in the two associated states.

  • Ephoton = AE = En:
  • - En = -2.18 x 10-18
  • 10-18 / 1
  • The frequency (\nu) can be calculated from the photon energy as
  • Ephoton = hv
  • V = Ephoton here h is Planck's constant.
  • Coming to a given transition, we can calculate the frequency as follows:
  • a. n=4 to n=3.
  • l
  • Photon energy can be calculated as
  • 1
  • Ephoton = AE = En:
  • - En, = -2.18 x 10-18
  • * 10-18
  • > Ephoton = -2.18 x 10-18
  • 1
  • 1.06 x 10-19
  • From this the photon frequency is calculated as
  • » - Epaten -
  • 1.06 x 10-19 )
  • 6.626 x 10-34 J.
  • 1.60 1014 -1
  • b. n=5 to n=1.
  • Photon energy can be calculated as follows 1
  • Ephoton = AE = En:
  • - En = -2.18 x 10-18
  • 8 x 10-18
  • → Ephoton = -2.18 x 10- 18 2.09 10-18 ]
  • So the photon frequency can be calculated as
  • c. n=5 to n=4.
  • The photon energy can be calculated as , the photon frequency can be calculated as n=6 to n=5.
  • The photon energy can be calculated as
  • 2.66 x 10-20

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