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An electromagnetic wave of wavelength 435nm is traveling in vacuum in the −z-direction. The electric field has amplitude 2.70×10−3V/m and is parallel to the x-axis.
Please answer the following part C correctly and show all steps.

Respuesta :

The energy of the electromagnetic wave is 1.4 × 10⁷.

Electromagnetic waves fluctuate from mechanical waves in that they do not require a medium to propagate. this means that electromagnetic waves can tour now not most effective through air and solid materials, but also thru the vacuum of space.

Calculation:-

The amplitude of the electric field is = 2.70 ×10⁻³ V/m

wavelength is = 435 nm

K =2π/λ

  =  2×3.141 / 435nm

  = 1.4 × 10⁷ J

Electromagnetic radiation includes waves of the electromagnetic discipline, which propagate thru an area and deliver momentum and electromagnetic radiant energy. It includes radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays.

Electromagnetic waves are shaped while an electric-powered discipline (which is shown in pink arrows) couples with a magnetic field (that's proven in blue arrows). Magnetic and electric fields of an electromagnetic wave are perpendicular to each different and to the direction of the wave.

Learn more about Electromagnetic waves here

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