The 3 ml liquid should be sufficient for a relatively low molecular weight liquid. the molecular weight increases, the volume of liquid becomes smaller.
Say the molar mass of the unkown liquid is provided
then,
boiling point of water at 1 atm = 100 oC = 100 + 273 = 373 K
standard STP temperature = 273 K
STP volume = 22.4 L
Temperature = (373/273) = 1.37
density = 0.65 g/ml
Volume of 3 ml liquid when evaporated
= ((3 x 0.65)g/molar mass x 22.4 x 1.37
So knowing molar mass we can easily calculate the volume occupied by 3 x 0.65 g of liquid in vapor phase.
The 3 ml liquid should be sufficient for a relatively low molecular weight liquid. However as the molecular weight increases, the volume of liquid becomes smaller.
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