If the density of your unknown liquid is 0.65 g/ml, calculate the volume in liters that 3 ml of your unknown liquid would occupy when vaporized at the barometric pressure and temperature of your boiling water bath in run 1. use the accepted molar mass of your suspected unknown.

Respuesta :

The 3 ml liquid should be sufficient for a relatively low molecular weight liquid. the molecular weight increases, the volume of liquid becomes smaller.

Say the molar mass of the unkown liquid is provided

then,

boiling point of water at 1 atm = 100 oC = 100 + 273 = 373 K

standard STP temperature = 273 K

STP volume = 22.4 L

Temperature = (373/273) = 1.37

density = 0.65 g/ml

Volume of 3 ml liquid when evaporated

= ((3 x 0.65)g/molar mass x 22.4 x 1.37

So knowing molar mass we can easily calculate the volume occupied by 3 x 0.65 g of liquid in vapor phase.

The 3 ml liquid should be sufficient for a relatively low molecular weight liquid. However as the molecular weight increases, the volume of liquid becomes smaller.

Learn more about molecular weight here : https://brainly.com/question/14596840

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