Respuesta :
The equation of the least-squares line when y is expressed in kilograms is y = 2114.20 + 18.96x.
What is the linear system?
A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more two variables.
The accompanying data resulted from an experiment in which weld diameter x and shear strength y (in pounds) were determined for five different spot welds on steel. A scatterplot shows a pronounced linear pattern.
Given the least square regression model equation:
y hat = -959.00 + 8.60x
weld diameter x ; shear strength y (in pounds)
1 lb = 0.4536 kg
To express shear strength y in kilogram:
y is multiplied by 0.4536
(y hat × 0.4536) = -959.00 + 8.60x
Divide both sides by 0.4536
(y hat × 0.4536) / 0.4536= (-959.00 + 8.60x) / 0.4536
y hat = 2114.1975 + 18.959435x
y hat = 2114.20 + 18.96x
The equation of the least-squares line when y is expressed in kilograms is y = 2114.20 + 18.96x.
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The question given by you is incomplete, the above answer is done as per a similar question
The accompanying data resulted from an experiment in which weld diameter x and shear strength y (in pounds) were determined for five different spot welds on steel. A scatterplot shows a pronounced linear pattern. The least-squares line is y hat = -959.00 + 8.60x. Because 1 lb = 0.4536 kg, strength observations can be re-expressed in kilograms through multiplication by this conversion factor: new y = 0.4536(old y). What is the equation of the least-squares line when y is expressed in kilograms? (Give the answer to two decimal places.)