When a nucleus of 235U undergoes fission, it breaks into two smaller, more tightly bound fragments. Calculate the binding energy per nucleon for 235U and for the fission product 137Cs .

Respuesta :

When a nucleus of 235u undergoes fission, it breaks into two smaller, more tightly bound fragments. The binding energy per nucleon for 235-U is 7.6 MeV and 137-Cs is 8.39 MeV.

In experimental physics, nuclear binding energy is the minimal amount of energy needed to separate an atom's nucleus into its component protons and neutrons, also known as nucleons.

The following equation provides the binding energy of a nucleus:

BE = Δmc² in which;

BE = Energy bound

Mass defect = m.

c = the speed of light = 931.49 MeV/u

For 235U:

A = 235

Δm = 1.9150664

BE = 1.9150664 x 931.49 MeV/u.

= BE = 1783.8648 MeV

The formula  of the nucleon's binding energy is BE/A

= BE/A = 235 x 1738.648 MeV

= BE/A = 7.6 MeV

The binding energy for 137-Cs will be:

Mass defect m = 1.23383 unit

= BE=1.123383 u x 31.49 MeV/u = 1149.3003 MeV

Additionally, the binding energy per nucleon, BE/A =

= A = 137

= BE/A = 137 x 1149.3003 MeV

= BE/A = 8.39 MeV

To know more about Binding Energy:

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