Respuesta :
The work done by the gas for question A will be 4.2 * 10^5 J.
The change in internal energy of the gas for question B is 6.43 * 10^5 J.
What is work (in gas)?
For a gas, it is the product of the pressure P and the volume V during a change of volume. The formula for work done in gas is W (work) = P (pressure) * V (volume)
Now, let's calculate the work done by gas to answer question A.
Work = Pressure * (Volume 2 - Volume 1)
= 1 atm * (16.2 - 12)
= 10^5 Pa * 4.2
= 4.2 * 10^5 J
So the work done by the gas is 4.2 * 10^5 J.
Now, let's find the change in internal energy of the gas.
The heat energy added to the system is
Q = 254kcal
= 254kcal * (4184J / 1 kcal)
= 1.063 * 10^6 J
The change in internal energy of gas is
ΔU = Q (the heat energy added) - W (work done by gas)
= 1.063 * 10^6 J - 4.2*10^5 J
= 6.43 * 10^5 J
Therefore, the change in internal energy of the gas is 6.43 * 10^5 J
Learn more about work (in gas) https://brainly.com/question/29589757
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