If parent 1 is heterozygous for both the "a" and the "b" alleles, this means that they have one copy of the dominant "A" allele and one copy of the recessive "a" allele for the "a" trait, and one copy of the dominant "B" allele and one copy of the recessive "b" allele for the "b" trait.
This means that parent 1 can produce two different types of gametes for each trait: those containing the "A" and "B" alleles, and those containing the "a" and "b" alleles.
Therefore, the possible gametes that parent 1 can produce in regards to these two traits are "A"/"B", "A"/"b", "a"/"B", and "a"/"b".
If parent 2 is homozygous recessive for the "a" allele and homozygous dominant for the "b" allele, this means that they have two copies of the recessive "a" allele for the "a" trait, and two copies of the dominant "B" allele for the "b" trait. This means that parent 2 can only produce gametes containing the "a" and "B" alleles.
Therefore, the possible gametes that parent 2 can produce in regards to these two traits are "a"/"B".
When the gametes from both parents combine during fertilization, there will be four possible combinations of alleles for each trait: "A"/"B", "A"/"b", "a"/"B", and "a"/"b".
These combinations will give rise to different genotypes and phenotypes in the offspring, depending on the dominant and recessive nature of the alleles.
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