The steps needed to prepare phenylacetylene C₆H₅C≡CH from C₆H₅CH₂CHBr₂ is as follows:
C₆H₅CH₂CHBr₂ + 2Na⁺ + ⁻NH₂ → C₆H₅C≡CH + 2HBr
The process involves two steps. Firstly, the alkyl halide is converted into alkynes with the help of a base (NaNH₂) which proceeds via an elimination reaction. The alkyne molecule is synthesized from the vicinal dihalides by two E₂ elimination reactions consecutively along with two equivalents of hydrogen halide.
In the second step synthesis of specified chemicals take place.
Phenylacetylene (C₆H₅C≡CH), is an alkyne hydrocarbon which has a colorless and thick appearance. It is more convenient for use in reactions than acetylene gas.
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