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An ice skater is gliding horizontally across the ice with an initial velocity of +6.94 m/s. The coefficient of kinetic friction between the ice and the skate blades is 0.0801, and air resistance is negligible. How much time elapses before her velocity is reduced to +2.92 m/s?

Respuesta :

The time elapses before her velocity is reduced to +2.92 m/s is 5.5 seconds.

How to calculate time elapses?

v = the initial velocity = 6.94 m/s

v0 = the reduced velocity = 2.92 m/s

μ =  the coefficient of kinetic friction = 0.0801

g = the gravity = 9.8 m/s^2 (assumed)

First we calculate the acceleration of the ice skater with this formula,

a = μ*g

= 0.0801 * 9.8 = 0.78498 m/s^2

Then, from basic formula about velocity, acceleration, and time which is,

a = (v-v0)/t

We can change the formula to calculate time. So,

t = (v-v0)/a

= (6.94-2.92)/0.78498

= 5.5 s

Thus, time needed to reduce velocity to +2.92 m/s is 5.5 seconds.

Learn more about acceleration here:

brainly.com/question/28537783

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