Find the volumes of the solids generated by revolving the regions bounded by the graphs of the equations about the given lines. y = x y = 0 x = 6 (a) X-axis (b) y-axis (c) x = 6 (d) x = 9 Find the volumes of the solids generated by revolving the regions bounded by the graphs of the equations about the given lines. y = 3x2 y = 0 x = 3 (a) y-axis (b) x-axis (c) y = 27 (d) X = 3 Find the volumes of the solids generated by revolving the regions bounded by the graphs of the equations about the given lines. y = x2 y = 6x - x2 (a) x-axis (b) y = 10

Respuesta :

Using rule of volume integral , The answer of y=x, y-=0 and x=6 is [tex]216 \pi[/tex].

What do you mean by integration?

The process of combining smaller parts into a single, cohesive whole is known as integration.

What do you mean by volume integral?

A volume integral is a specific instance of multiple integrals and is used to denote an integral across a 3-dimensional domain in mathematics, notably multivariable calculus. In physics, volume integrals are crucial for many applications, such as calculating flux densities.

area covered by y=x y=0 and x=6 is [tex]\frac {1}{2} * 6 * 6[/tex]

=18 [tex]unit^{2}[/tex]

Perimeter covered by revolving the area about x-axis, y-axis , x=6 and x=9 is [tex]2*\pi *6[/tex]

=[tex]12 \pi[/tex]

Volume = [tex]18 * 12 \pi[/tex]

=[tex]216 \pi unit ^{3}[/tex]

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