Consider an electrochemical cell formed from a Cu(s) electrode submerged in an aqueous Cu(NO_3)_2 solution and a Cd(s) electrode submerged in a Cd(NO_3)_2(aq) solution. The two electrodes are connected by a wire and the two solutions are connected by a salt bridge containing NaNO_3(aq). The following reaction takes place: Cu^2+(aq) + Cd(s) rightarrow Cu(s) + Cd^2+(aq) Which statement describes how the electrons or nitrate ions will flow? electrons will flow from Cu(s) to Cd(s) nitrate ions will flow from Cu compartment to Cd compartment nitrate ions will not flow between compartments nitrate ions will flow from Cd compartment to Cd compartment

An electrochemical cell is a device that uses electricity to induce a nonspontaneous process or to generate electricity from a spontaneous oxidation-reduction reaction.

Since in the given reaction Cu2+ is going to reduce to Cu and Cd is going to oxidize to Zn2+ . Electrons and cadmium ions will move towards cathode where reduction occurs.

And nitrate ions will move towards anode to maintain a neutral charge, where oxidation occurs.

So, nitrate will flow from Cu compartment to Cd compartment.

Therefore, option B is the right answer, Nitrate ions will flow from Cu compartment to Cd compartment.

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