let d be a positive integer. show that among any group of d 1 (not necessarily consecutive) integers there are two with exactly the same remainder when they are divided by d.

Respuesta :

Among any group of d+1 integers there are two with exactly the same remainder when divided by d.

What are Positive Integers?

Positive integers are those bigger than 0 that don't contain any fractional portions. On the number line, these figures are located to the right of 0.

Is 0 a Positive Integer?

Since it is neither positive nor negative, 0 is not a positive integer. Positive integers are defined as numbers greater than 0 in mathematics.

The possible remainders after dividing an integer by d are 0, 1, 2,..., d-1.

The number of remainders that can be obtained is d, or |0, 1, 2,..., d-1|=d0,1,2,...,d-1=d.

According to the Pigeonhole Theory:

objects are the number of integers in d+1.

"holes" = "remainders" + "d"

[d+1/d]=2

According to the Pigeonhole Principle, there are always two d+1 integers in every group that have precisely the same residual after being divided by d.

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There are always two d+1 numbers in any group that have the exact same residual after division.

Examples of integers and what they are:

An integer, pronounced "IN-tuh-jer," is an entire number which can be positive, minus, even zero and is not a fraction. Integer examples include: -5, 1, 5, 8, 97, among 3,043. 1.43, 1 3/4, 3.14, and other values which aren't integers seem to be some examples.

Briefing:

The potential remainders after dividing an integer by d are 0, 1, 2,..., d-1.

The possible number of remainders is d, or I{0,1,2,.......d-1}I = d

By the Pigeonhole Principle:

Objects = umber of integers = d+1

Holes = number of remainders = d

[tex]\frac{d+1}{d} = 2[/tex]

According to the Pigeonhole Principle, there are always two d+1 numbers in every group that have precisely the same residual after being divided by d.

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https://brainly.com/question/15276410

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