The average shear stress, Tavg, is equal to 0.06 pu2., Solving for the drag coefficient of the bar, CD, yields: 2.40.
What is shear stress?
An object experiences deformation whenever an external force acts upon it. if the force's direction is parallel to the object's plane. Along that plane, there will be a deformation. The object in this instance is under shear or tangential stress. It happens so when force vector components that are perpendicular to the material's cross-sectional area. The force vectors for normal/longitudinal stress will be parallel to the cross-sectional area that it affects.
(a) The average shear stress, Tavg, is equal to the dynamic pressure pu2 divided by the width of the bar, h. Therefore,
Tavg = pu2/h
Rearranging for the dynamic pressure pu2 yields:
pu2 = Tavg h
Substituting the given value of Tavg as 0.06 pu2 gives:
pu2 = 0.06 pu2 x h
Solving for h yields:
h = pu2/0.06 pu2
Therefore, the average shear stress, Tavg, is equal to 0.06 pu2.
(b) The drag coefficient of the bar, CD, is equal to the drag force (Fd) divided by the dynamic pressure (pu2) times the area (A) of the bar. Therefore,
CD = Fd/(pu2 x A)
Rearranging for Fd yields:
Fd = CD x pu2 x A
Substituting the given values for CD, pu2, and A gives:
Fd = 2.40 x pu2 x (h x L)
Solving for the drag coefficient of the bar, CD, yields:
CD = Fd/(pu2 x A) = 2.40
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