Respuesta :
a. Spring constant which has a maximum mass velocity of 25.0 cm/s and a period of 0.450 s = 17.49 N/m.
b. The amplitude of the motion of the spring = 0.0179 m.
c. Frequency of oscillation of the spring = 2.22 Hz.
The angular velocity
Briefly, angular velocity is the angular speed accompanied by the direction. The unit of angular speed is rad/s or rad/minute or rad/hour.
Some of the equations that are often used are:
ω = [tex]\sqrt{\frac{k}{m}}[/tex]
ω = 2π/T
ω = angular velocity (rad/second)
k = the spring constant
m = mass of the object
f = frequency (rev/second)
T = period (second)
The question is incomplete, it should be:
Find the
a. constant of the spring?
b. amplitude of the motion?
c. frequency of oscillation?
We have,
Mass of the object = 90.0 g
The maximum speed = 25.0 m/s
The period = 0.450 s
Determine the angular velocity first,
ω = 2π/T
= 2π/0.450
= 4.44 π rad/s
So,
a. Spring constant:
ω = [tex]\sqrt{\frac{k}{m}}[/tex]
k = ω²m
= (4.44 π rad/s)² (0.09)
= 17.49 N/m.
b. The amplitude:
vm = (xm) (ω)
So, xm = vm/ω
= 0.25/4.44 π
= 0.0179 m
c. The frequency:
f = 1/T
= 1/0.450
= 2.22 Hz.
Learn more about angular velocity here: https://brainly.com/question/29672590
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