A mass of 0.520 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x(t) = (0.780 m)cos[(18.0 rad/s)t]. Determine the following. (a) amplitude of oscillation for the oscillating mass (b) force constant for the spring N/m (c) position of the mass after it has been oscillating for one half a period (d) position of the mass one-third of a period after it has been released How can you determine the position of the object at a specific time from an expression for the position of the object at any time? m (e) time it takes the mass to get to the position x = −0.500 m after it has been released (s)

Respuesta :

a) The amplitude of oscillation is 0.780 m.

b) The force constant of the spring can be determined by using the equation F=kx, where F is the force applied to the mass, k is the force constant, and x is the displacement of the mass. Since the displacement of the mass is 0.780 m, we can solve for k to get k = F/x = 0.780 N/m.

c) The position of the mass after one half a period is given by x(t) = (0.780 m)cos[(18.0 rad/s)t] = (0.780 m)cos[(9.0 rad/s)t] = 0.780 m.

d) The position of the mass one-third of a period after it has been released is given by x(t) = (0.780 m)cos[(18.0 rad/s)t] = (0.780 m)cos[(6.0 rad/s)t] = -0.500 m.

e) To determine the time it takes the mass to get to the position x=-0.500 m after it has been released, we can use the equation x(t) = (0.780 m)cos[(18.0 rad/s)t]. Since we know that x=-0.500 m when t=t0, we can solve for t0 to get t0=6.00 s. Therefore, it takes the mass 6.00 s to get to the position x=-0.500 m after it has been released.

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