A 16-byte cache block can store 4 32-bit integers. To determine how many 32-bit integers can be stored in a 16-byte cache block, we need to divide the size of the cache block (in bytes) by the size of a single 32-bit integer (in bytes).
A 16-byte cache block can store 4 32-bit integers because the size of the cache block determines the maximum number of bytes that can be stored in it, and the size of the 32-bit integers determines how many of them can fit in the cache block. By dividing the size of the cache block by the size of the integers, we can determine how many integers can fit in the cache block.
Here is the computation:
Since a 32-bit integer is 4 bytes, we can calculate the number of 32-bit integers that can be stored in a 16-byte cache block as follows:
16 bytes / 4 bytes/integer = 4 integers
Therefore, a 16-byte cache block can store 4 32-bit integers.
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