In thi exercie we look at memory locality propertie of matrix computation. The following code i written in C, where element within the ame row are tored contiguouly. Aume each word i a 32-bit integer. How many 32-bit integer can be tored in a 16-byte cache block?

Respuesta :

A 16-byte cache block can store 4 32-bit integers. To determine how many 32-bit integers can be stored in a 16-byte cache block, we need to divide the size of the cache block (in bytes) by the size of a single 32-bit integer (in bytes).

A 16-byte cache block can store 4 32-bit integers because the size of the cache block determines the maximum number of bytes that can be stored in it, and the size of the 32-bit integers determines how many of them can fit in the cache block. By dividing the size of the cache block by the size of the integers, we can determine how many integers can fit in the cache block.

Here is the computation:

Since a 32-bit integer is 4 bytes, we can calculate the number of 32-bit integers that can be stored in a 16-byte cache block as follows:

16 bytes / 4 bytes/integer = 4 integers

Therefore, a 16-byte cache block can store 4 32-bit integers.

Learn more about cache block, here https://brainly.com/question/29744305

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