Respuesta :
Yes, there is something wrong with the function.
Here, two integer variables, num1, and num2 are taken by this function as arguments. Then it assigns the value of num1 to a newly declared integer variable, temp. It then assigns the value of temp to num2, and the value of num2 to num1, thus swapping the values of the two variables effectively.
Here, the problem with the function is that the function operates on copies of the original variables rather than the variables themselves.
The variables num1 and num2 are passed by value, which means that to swap the values of the original variables, the function should use pointers or pass the variables by reference.
For example
void swap (int* num1, int* num2) {
int temp = *num1;
*num1 = *num2;
*num2 = temp;
}
Here, the function to modify the original variables directly as the variables num1 and num2 are passed as pointers.
To learn more about Integer functions visit
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Complete Question
The following function should swap the values contained in two integer variables, num1, and num2. What, if anything, is wrong with this function?
void swap(int num1, int num2)
{
int temp = num2;
num2 = num1;
num1 = temp;
}
