Calculate the amount of energy (in kJ) necessary to convert 450g of liquid water from 38°C to water vapor at 125 C. The molar heat of vaporization (Hvap) of water is 40.79 kJ/mol. The specific heat for water is 4.184 J/g C, and for steam is 1.99 J/g C. (Assume that the specific heat values do not change over the range of temperatures in the problem.)

Respuesta :

total amount of energy required is= 132.6 + 717.9 + 45.42 = 896 kJ to convert 450g of liquid water from 38°C to water vapor at 125 C. The molar heat of vaporization (Hvap) of water is 40.79 kJ/mol. The specific heat for water is 4.184 J/g C, and for steam is 1.99 J/g C.

cslculation-heat energy required to raise the temp of liquid water to 100 C = 317 * 4.184 * 100 = 132632 J =132.6 kJ,mole of water = 317 / 18 = 17.6 mol,heat required for vaporization = 17.6 * 40.79 = 717.9 kJ,Heat required to raise the temp of water vapor to 172 C = 317 * 1.99 * 72 = 45420 J = 45.42 kJ, total heat required  = 132.6 + 717.9 + 45.42 = 896 kJ. The quantity of heat necessary to increase the temperature of one unit mass of a substance by one degree Celsius. The specific heat capacity of a substance is specified as the amount of heat (J) soaked up per unit mass (kg) when its temperature rises 1 K (or 1 °C). The specific heat capacity of a substance is typically calculated by monitoring the heat capacity of a specimen of the material, generally with a calorimeter, and trying to divide by the sample's mass. The average kinetic energy of each molecule increases as the substance heats up.

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