The reaction that treated with KOH in ethanol is explained by the E2 Elimination.
Compound has the molecular formula C9H19Cl and when treated with KOH, ethanol is obtained. haloalkanes that on reaction with a base form an alkene as the major product 2-chloro-2,6-dimethylheptane and 3-bromo-2,6-dimethylheptane respectively. On reaction with base, both the compounds form 2,6-dimethylhept-2-ene as major product via E2-elimination. This major product is decided by Zaitsev's rule. The alkene reacts with one mole H2 to form 2,6-dimethylheptane via addition reaction. Reaction with HCl occurs via Markovnikov addition, chlorine group is added to second carbon and 2-chloro-2,6-dimethylheptane is formed again. Therefore, 2-chloro-2,6-dimethyheptane and 3-bromo-2,6-dimethylheptane.
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