v = 7.27 m / s
Explanation:
At both the greatest and lowest points, we shall practise energy conservation.
first. The highest point
Em₀ = U
Em₀ = m g y
final. smallest point
At this point, we adjust the reference system so that the potential energy is 0
= K
= ½ m v²
how to conserve energy
Em₀ =
mg y = ½ m v²
v = √2 gy
v = √ (2 9.8 2.7) (2 9.8 2.7)
v = 7.27 m / s
To learn more about practise please click on below link
https://brainly.com/question/14192783
#SPJ4
