The general indefinite integral of ([tex]e^{x}[/tex]+ 1/8x) is ∫([tex]e^{x}[/tex]+ 1/8x) dx
= [tex]e^{x}[/tex]+ 1/4x + C
An integral is considered to be indefinite if it has no upper or lower bounds.
The most generic anti-derivative of f(x) is known as an indefinite integral and denoted, in mathematics, by F(x), which is any anti-derivative of f(x).
f(x) dx = F(x) + C
The integral of [tex]e^{x}[/tex] = [tex]e^{x}[/tex]
so ∫[tex]e^{x}[/tex] dx = [tex]e^{x}[/tex] + C
The integral of 1/8x = 1/4x,
so ∫1/8x dx = 1/4x + C
To find the integral of ([tex]e^{x}[/tex] + 1/8x), add the integrals of each term:
∫([tex]e^{x}[/tex]+ 1/8x) dx = [tex]e^{x}[/tex] + 1/4x + C
To know more about the general indefinite integral visit here:
https://brainly.com/question/3692745
#SPJ4
