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A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its axis of symmetry. The receiver is to be located at the focus. If the dish is 24 feet across at its opening and 2 feet deep at its center, where should the receiver be placed?
Find the equation of the parabola?
How far above the vertex should the receiver be placed?

Respuesta :

Equation of parabola: y =ax² and receiver should be placed 18 feet above vertex.

Explanation:

Considering satellite dish as parabola we can have vertex as origin and concave upward.

So, equation of parabola will be justifying structure of satellite dish i.e

y = ax² -------(1)

Two points other than (0,0) are (-12,2) and (12,2), unit being feet.

This points will satisfy equation of parabola, substituting them in equation 1, we will calculate the value of constant 'a'.

a = [tex]\frac{2}{12^{2} }[/tex]

[tex]\frac{2}{2*6*12}\\ =\frac{1}{72}[/tex]

Substituting value of a = 1/72 in equation 1 we get

72y = x²

As receiver need to be located at focus, so it will be places at a distance of 'p' above the vertex

4p = 72

Dividing both sides by 4, we get

p = 18 feet

So, receiver will be placed at a distance of 18 feet above vertex.

Learn more about parabola here:

https://brainly.com/question/64712

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