According to the question the ratio of the flow rates in the two pipes is [tex]\sqrt{3}[/tex] /1
Fluid Flow, a branch of fluid dynamics, is concerned with fluids. It involves the movement of a fluid under the influence of uneven forces. As soon as unbalanced pressures are applied, this motion will persist.
Lets take
Length of pipe B = L
Length of pipe A = 3 L
Discharge in pipe A = Q₁
Discharge in pipe B = Q₂
[tex]h_{f}[/tex] = (FLQ²)/12.1.[tex]d^{5}[/tex]
F=Friction factor, Q=Discharge,L=length
d=Diameter of pipe
here all only Q and L is varying and all other quantity is constant
So we can say that
LQ²= Constant
L₁Q₁²=L₂Q²₂
By putting the values
3LQ₁²=LQ²₂
Therefore
[tex]Q_{1}[/tex]/ [tex]Q_{2}[/tex] =[tex]\sqrt{3}[/tex]/ 1
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