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Triangle XYZ is shown on the coordinate plane.

A triangle on the coordinate plane with vertices X at 0 comma 5, Y at 10 comma 3, and Z at 4 comma negative 1.

If triangle XYZ is translated using the rule (x, y) → (x + 2, y + 3) and then reflected across the x-axis to create triangle X″Y″Z″, what is the location of Z″?

(2, −8)
(6, −2)
(8, −2)
(12, −6)

Triangle XYZ is shown on the coordinate plane A triangle on the coordinate plane with vertices X at 0 comma 5 Y at 10 comma 3 and Z at 4 comma negative 1 If tri class=

Respuesta :

If triangle XYZ is translated using the rule (x, y) → (x + 2, y + 3) and then reflected across the x-axis to create triangle X″Y″Z″, the location of Z″ would be; (6, −2)

How to carry out Translation of triangles?

The coordinates of the given triangle are;

X(0, 5)

Y(10, 3)

Z(4, -1)

The triangle XYZ is translated using the rule (x, y) → (x + 2, y + 3). Thus, the new coordinate of Z will be;

Z'(4 + 2, -1 + 3) = Z'(6, 2)

When we reflect about the x-axis, the transformation rule will be;

(x, y) = (x, -y)

Thus, the final coordinate of Z after reflection about the x-axis is Z"(6, -2)

Read more about translation at; https://brainly.com/question/12861087

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