Respuesta :
160 Hz is the higher harmonics of a string fixed at both ends that has a fundamental frequency of 80 Hz.
According to this option c) is correct answer.
A string's fundamental frequency, succeeding frequencies, and two ends are defined as the sum of the entire depending on the number of harmonics. In other words, higher harmonics specify the frequencies that follow under the functions 2f, 3f, 4f, 5f, etc.
As a result, the higher harmonics would be:
1 x 80 Hz Equals 80 Hz (1st harmonic and Fundamental Frequency)
2 × 80Hz Equals 160Hz (2nd harmonic) (2nd harmonic)
3 x 80Hz Equals 240Hz (3rd harmonic)
4 × 80Hz = 320Hz (4th harmonic)
5 x 80Hz Equals 400Hz (5th harmonic)
As a result, the two higher harmonics of a string with an 80Hz fundamental frequency are 160Hz and 240Hz.
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I understand that the question you are looking for is:
Select the higher harmonics of a string fixed at both ends that has a fundamental frequency of 80 Hz.
a)280 Hz
b) 400 Hz
c) 160 Hz
d) 200 Hz
e) 180 Hz
