Because the acid is much more concentrated and the reaction will proceed more quickly, the mole ratios will be larger.
For instance, use 250 MG of concentrated acid to create 500 mL of 6M HCl, which you then gradually diluted with water.
6M HCl has half the concentration of 12M HCl, therefore a solution that is 50% 12M HCl, is a 6M solution. To make 0.5L of 6M HCl, you would need 0.25 (half of 0.5) litres of 12M HCl
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