On solving, the given system reduces to x1 = 12, & x2 = —7 which is the required solution.
Linear algebra is a subfield of mathematics that mostly uses matrices. When you start solving linear equation systems, linear algebra first starts to seem good. You may concentrate on the figures and greatly simplify the procedure by condensing all the information into a single large chart and leaving out the rest.
Almost as their name implies, square, symmetric, triangular, and diagonal matrices. All-zero identity matrices except along the major diagonal, where the values are
T he augmented matrix of the given system is B =
[tex][AB] = \left[\begin{array}{ccc}2&4&-4\\5&7&11\\\end{array}\right] \\on solving we get \\ [AB] = \left[\begin{array}{ccc}1&0&12\\0&1&-7\\\end{array}\right] \\[/tex]
Hence the given system reduces to x1 = 12 x2 = -7
Hence the given system reduces to
x1 = 12, & x2 = —7
which is the required solution.
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