Reconsider the paint-drying situation of Example 8.2, in which drying time for a test specimen is normally distributed with σ = 9. The hypotheses H0: μ = 75 versus Ha: μ < 75 are to be tested using a random sample of n = 25 observations.

Respuesta :

A random sample of n = 25 observations will be used to test the hypotheses H0: Î14 = 75 and Ha: Î14 75.the test statistic is lower than -1.96, we can reject the null hypothesis and conclude that the mean drying time is less than 75.

H0: μ = 75

Ha: μ < 75

Test Statistic: z = (x - μ) / (σ / √n)

critical Value: z crit = -1.96

Conclusion: Reject H0 if the test statistic is less than -1.96.

We can test the hypotheses H0: μ = 75 versus Ha: μ < 75 by using the test statistic z = (x - μ) / (σ / √n). The critical value for this test is z crit = -1.96. The decision rule for this test is to reject H0 if the test statistic is less than -1.96. This means that if the test statistic is lower than -1.96, we can reject the null hypothesis and conclude that the mean drying time is less than 75.

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