The speed with which the squid ejects the water is 42 m/s. If we ignore lift and drag forces, the maximum horizontal range that the squid can achieve before splashing down is about 1.25 m
From the conservation of momentum,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(36 kg) (3.5 m/s) - (3 kg) v = 0
(3 kg)v= (36 kg) (3.5 m/s)
v = 42 m/s
Hence, required speed is 42 m/s.
The maximum horizontal range is,
R = u ² sin 20/g
Rmax = u²sin 2 (45°)/g
= (3.5 m/s) ² sin 90° / 9.8
=1.25 m
The maximum horizontal range is 1.25 m.
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