Draw a Lewis structure for SO2 in which all atoms obey the octet rule. Show formal charges. Do not consider ringed structures.
Draw a Lewis structure for SO2 in which all atoms have a formal charge of zero. Explicitly showing the zero charges is optional. Do not consider ringed structures.

Respuesta :

In SO2, both the oxygen atoms have same number of unshared and shared electrons. so they have formal charge of zero. this explains from the Lewis structure.

Lewis structure shows the bonding between atoms in a molecule and also shows lone pair of electrons present on the atoms. Charge on an atom without considering electronegativity differences is called as formal charge. Sulphur belongs to group 6A of the periodic table. Thus, Sulphur has 6 valance electrons atom is 6. Sulphur atom also has 6 valance electrons. Total number of valance electrons is 18. All the atoms in the molecule are connected with covalent bonds. Lone pairs of electrons are also added to each atom. Each atom of the molecule has octet. Both the oxygen atoms have same number of unshared and shared electrons. So, they have formal charge of zero. Thus, formal charges on all the atoms are zero.

Octet rule is a rule of thumb in determining where the valance electrons orient themselves or are shared. It implies that every element would want to fill its s and p orbitals in the valence electron shell.

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