Cells that have a high level of reactive oxygen species would need which of the following pathway(s) to be active in order to reduce the high level of oxidative stress?
A. Oxidative Phase of PPP
B. Non-Oxidative Phase of PPP
C. Glycolysis
D. Gluconeogenesis
More NADPH --> oxidative phase
non-oxidative phase--> fructose 6- bisphosphate and 3 glyceraldehyde
gluconeogensis: convert it to fructose 6- bisphosphate and 3 glyceraldehyde to make even more glucose
Since the cell needs high levels of NADPH. The pathways that would provide the most NADPH would be the oxidative phase of PPP, the non-oxidative phase of PPP producing fructose 6-phosphate and glyceraldehyde 3-phosphate, and gluconeogenesis using fructose 6-phosphate and glyceraldehyde 3-phosphate to produce more glucose 6-phosphate that can be used to generate more NADPH.

This segment is made up of two irreversible steps: Step 1: Glucose-6-phosphate is oxidized to shape lactone. NADPH is produced as a byproduct of this response as NADP +begin superscript, plus, cease superscript is decreased as glucose-6-phosphate is oxidized.

More NADPH --> oxidative phasenon-oxidative segment--> fructose 6- bisphosphate and three glyceraldehydegluconeogensis: convert it to fructose 6- bisphosphate and three glyceraldehyde to make even extra glucose

Since the mobileular wishes excessive ranges of NADPH. The pathways that might offer the maximum NADPH will be the oxidative segment of PPP, the non-oxidative segment of PPP generating fructose 6-phosphate and glyceraldehyde 3-phosphate, and gluconeogenesis the usage of fructose 6-phosphate and glyceraldehyde 3-phosphate to provide extra glucose 6-phosphate that may be used to generate extra NADPH.