The wavelength of the light if a monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35mm is 506.25 nm
When a wave is bent by an obstruction whose dimensions are close to the wavelength, diffraction is noticed. We can disregard the effects of extremes because the Fraunhofer diffraction is the simplest scenario and the impediment is a long, narrow slit.
This is a simple situation where the Fraunhofer single slit diffraction equation can be applied:
y = mλ D
α
where,
y = displacement from the centerline for minimum intensity = 1.35 mm
m = order number = 1
λ = light wave length
α = witdh of the slit = 0.750 mm
D = distance between the screen and the slit = 2m
so
λ = yα
mD
λ = (1.35 x 10⁻³)( 0.750 x 10⁻³) = 5.0625 x 10⁻⁷m = 506.25 nm
1x2
learn more about the Fraunhofer single slit diffraction at https://brainly.com/question/19865648
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