The incorrect options for the program set the sign flag (SF) to 1 if the original value in al is negative, otherwise SF should be se to 0 is not al.
Xor, and, or, not is called as binary operation. Binary operation is operation to combine two binary number to produce another number.
To know the incorrect options we will evaluate each option,
For xor al, 0
The program is to xor-ing each value of al by 0. Xor result will be 1 if only single 1 in set. i.e.
0 xor 0 = 0
0 xor 1 = 1
1 xor 0 = 1
1 xor 1 = 0
So, this operation will keep the highest bit, and set the SF accordingly.
For or al, 0
The program is to or-ing each value of al by 0. Or result will be 1 except if both input is 0. i.e.
0 or 0 = 0
0 or 1 = 1
1 or 0 = 1
1 or 1 = 1
So, this operation will keep the highest bit, and set the SF accordingly.
For and al, al
The program is to and-ing each value of al by itself. And result will be 1 if only both input is 1. i.e.
0 or 0 = 0
0 or 1 = 0
1 or 0 = 0
1 or 1 = 1
So, this operation will keep the highest bit, and set the SF accordingly.
For not al
The program is to not-ing each value of al. Not result will be flipping the value. i.e.
not 0 = 1
not 1 = 0
So, this operation will flip the highest bit, and set the SF wrongly.
So, the wrong option is not al
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