Respuesta :
With the help of Punnett square, we can determine that there is a 25% probability of getting an f2 offspring that is homozygous recessive for both traits.
To determine the probabilities, we can utilize a Punnett square table or just do some simple scenario planning. Each parent has a genotype of Ff, where each allele has an equal chance of being passed on to a child. Therefore, there is a 50% chance that a parent will contribute the dominant allele F1 and a 50% chance that a parent will contribute the recessive allele f2. Here is a list of the possibilities:
There is a 50% x 50% = 25% probability that both of the offspring's alleles are dominant.
There is a 50% x 50% = 25% probability that both of the offspring's alleles are recessive and homozygous.
There is a 50% x 50% + 50% x 50% = 25% + 25% = 50% probability that the offspring is heterozygous.
Therefore, for parents who share the genotype F1F2, there is a 25% chance that their offspring will be F1F1, a 25% chance that they will be F2F2, and a 50% chance that they will be F1F2. These probabilities are significant because of what comes afterward.
The complete question is:
When Mendel set up a Parental (P) cross between true-breeding purple and white flowered plants to generate the F1 and then allowed the F1 to self-pollinate to generate the F2 he saw a dominant-to-recessive ratio of 3:1, how would you determine the probability of getting an f2 offspring that is homozygous recessive for both traits?
To learn more about recessive alleles please click on the given link: https://brainly.com/question/1217908
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