Respuesta :
The 95% confidence interval for the difference between the two proportions is (0.056, 0.164)
Here, we are given that from the sample information for people under 18-
n₁ = 500
x₁ = 180
⇒ p₁ = 180/ 500
p₁ = 0.36
then,
q₁ = 1 - p₁
q₁ = 0.64
Similarly, from the sample information for people over 18, we have-
n₂ = 600
x₂ = 150
⇒ p₂ = 150 / 600
p₂ = 0,25
then,
q₂ = 1 - p₂
q₂ = 1 - 0.25
q₂ = 0,75
Now, we conduct a hypothesis test as follows-
Null hypothesis (H₀) ⇒ p₁ = p₂
Alternative Hypothesis (Hₐ) ⇒ p₁ ≠ p₂
Confidence interval = 95 %
⇒ significance level (α) = 5 %
α = 0.05
and α/ 2 = 0.025
⇒ z at 95% significance level = 1.96 (from z tables)
Now, we calculate z statistic-
z(s) = (p₁ - p₂) / EED
EED = √[(p₁*q₁)n₁ + (p₂*q₂)/n₂]
EED = √[( 0.36*0.64)/500 + (0.25*0.75)/600]
EED = √[0.00046 + 0.0003125]
EED = 0.028
and (p₁ - p₂) = 0.36 - 0.25
= 0.11
Therefore,
z(s) = 0.11 / 0.028
z(s) = 3.93
we can see that z(s) > 1.96
⇒ z(s) is in the rejection region for H₀
Thus, we reject H₀. We can´t support the idea of equals means
Now, CI at 95 % = (p₁ - p₂) ± z(c) * EED
CI = (0.11 ± 1.96 * 0.028)
CI = (0.11 ± 0.054)
CI = (0.056, 0.164)
Thus, the 95% confidence interval for the difference between the two proportions is (0.056, 0.164)
Learn more about hypothesis testing here-
https://brainly.com/question/15980493
#SPJ4
Your question was incomplete. Check for missing content below-
Q1. Let P, represent the proportion under and p, the proportion over the age of 18. The null hypothesis is:_____.
Q2. The 95% confidence interval for the difference between the two proportions is:____.