Angle of the first order maximum is 35.1°.
Given,
frequency f= 2000 Hz
sound travels average 352 m/s
The speed of the sound wave is 352 meters per second, and the Frequency is 2000. The slate is separated by 30 cm. The position of the first order needs to be found. There is a maximum for interference.
a) wavelength = v/f = 352/2000
λ = d sinФ
Ф = si[tex]n^-^1[/tex]( (352/2000)/.3)= 35.4°
The speed of sound can be written as 52 meter per second if the Frequency is 2000 times one over the separation. The first order's maximum is 35.4 degrees.
b) then λ/d
=(352/2000)/.3 = 2.85E-2/d
d=0.0496 m
c) (352/3000)/.3 = (352/f)/1.0E-6
f= 9.0E8 Hz
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