No , the carpeted rooms does not have more bacteria than uncarpeted rooms .
Given ,
α=0.05
n1=8
n2 = 8
mean = ∑x / n
x1 = 11.8+10.8+7.1+14.6+8.2+10.1+13.0+14.0 / 8 = 11.2
and
x2 =12.1+12.0+3.8+10.1+8.3+11.1+7.2+13.7 /8 = 9.78
Variance ,
s1 =2.6
s2 = 3.2
HYPOTHESES
H0 : μ 1 =μ 2
H1 : μ 1 ≠μ 2
Either the alternative hypothesis or the null hypothesis applies to the claim. The equality must be present in the null hypothesis. The alternative hypothesis declares the opposite of the null hypothesis if the claim is the null hypothesis.
On calculating we get the test statistic t as,
t = 1.771
The null hypothesis is rejected if the test statistic's value falls within the rejection zone.
0.956<1.771,
therefore , fail to reject H .
Therefore , there is no support for the null hypothesis , so we accept the alternate hypothesis as true.
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