Respuesta :
The period of oscillation of the Taipei 101 building is 13 seconds .
In the question ,
it is given that ,
the length of the cables(L) is = 42 m
the mass of the mass damper is = 660000 Kg ,
the amplitude is = 75 cm = 0.75 m
we know that the acceleration due to gravity(g) is = 9.8 .
the formula for the Time Period (T) is
T = 2π√(L/g)
Substituting the values ,
we get ,
T = 2π√(42/9.8)
Simplifying further ,
we get ,
T = 13.00079 seconds
T ≈ 13 seconds .
Therefore , the period of oscillation is = 13 seconds .
The given question is incomplete , the complete question is
Taipei 101 (a 101-story building in Taiwan) is sited in an area that is prone to earthquakes and typhoons, both of which can lead to dangerous oscillations of the building. to reduce the maximum amplitude, the building has a tuned mass damper, a 660,000 kg mass suspended from 42-m-long cables that oscillates at the same natural frequency as the building . when the building sways, the pendulum swings, reaching an amplitude of 75 cm in strong winds or tremors. damping the motion of the mass reduces the maximum amplitude of oscillation of the building .
What is the period of oscillation of the building?
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