Respuesta :
Expected time = (Optimistic time + 4* Most Probable time + Pessimistic time) / 6 Variance = (S.D.)2
Standard deviation = (Optimistic time - Optimistic time) / 6 The critical path is B-E-H-J, with an expected duration of 26 weeks (4+10+7+5) and a variance of 4.11 or a standard deviation of 2.03 The project time (say X) has a normal distribution Z=.49261),
so the probability that the project will be finished in 25 weeks is.311, and Prob. (30) = Prob. Z = 1.97), so the project's 30-week completion rate is.975 percent.
Critical Activity Expected Time Variance A 4 0.11 No B 4 0.44 Yes C 5 0.11 No D 3 0.11 No E 10 1.78 Yes F 9 0.69 No G 6 0.25 No H 7 1.78 Yes, I 3 0.44 No J 5 0.11 No.
In PERT, how is optimistic and pessimistic time calculated?
As its inputs, PERT employs estimates of Pessimistic, Optimistic, and Most Likely. (Pessimistic + 4x Most Likely + Optimistic) / 6 is the traditional (beta) PERT formula. C. Sprightly's normal worth estimation, utilizing the customary Beta conveyance, is as per the following: [ optimistic, pessimistic, and (four times most likely)]/6.
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Full Question = the product development group at landon corporation has been working on a new computer software product that has the potential to capture a large market share. through outside sources, landon's management learned that a competitor is working to introduce a similar product. as a result, landon's top management increased its pressure on the product development group. the group's leader turned to pert/cpm as an aid to scheduling the activities remaining before the new product can be brought to the market. the project network is as follows.
The activity time estimates (in weeks) are as follows:
Activity Optimistic Most Probable Pessimistic
A 3 4 5
B 3 3.5 7
C 4 5 6
D 2 3 4
E 6 10 14
F 7.5 8.5 12.5
G 4.5 6 7.5
H 5 6 13
I 2 2.5 6
J 4 5 6
