The concentration (in mol/L) of calcium ions in solution after the reaction has gone to completion. 75.0 mL of 1.50 M AgNO, are mixed with 75.0 mL of 2.1 M is 0.75 mol / L.
The reaction is given as :
2AgNO₃(aq) + CaCl₂(aq) -----> Ca(NO₃)₂(aq) + 2AgCl(s)
moles of AgNO₃ = molarity × volume
= 1.50 × 0.075
= 0.1125 mol
moles of CaCl₂ = 2.1 × 0.075
= 0.1575 mol
AgNO₃ is a limiting reactant ,2mole of AgNO₃ produces 1 mole of Ca(NO₃)₂
moles of Ca(NO₃)₂ = 0.1125 / 2 = 0.05625 mol
concentration of Calcium ion is = 0.05625 / 0.075
= 0.75 mol/ L
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