contestada

the figure(figure 1) shows a particle of mass m at distance x along the axis of a very thin ring of mass m and radius r. calculate the gravitational potential energy of these two masses. use what you know about the relationship between force and potential energy to find the magnitude of the gravitational force on m when it is at position x>0 .

Respuesta :

The magnitude of the gravitational force on mass m  at distance x along the axis of a very thin ring when it is at position x>0  is 4GMm/4x^2-L^2.

Every body in the universe attracts every other body with a gravitational force that decreases with distance as 1/r2.  if two bodies of different masses have the same acceleration they must be feeling forces in the same ratio as their masses (so a body twice as massive feels twice the gravitational force), that is, the gravitational force of attraction a body feels must be proportional to its mass.

The gravitational field at any point P in space is defined as the gravitational force felt by a tiny unit mass placed at P.

This relation can be find out by using the formula of gravitational potential = GMm/r and further integrating on small dx length at x from the origin of the rod, we get,

U = GMm/L㏑2x-2/2x+2.

now differentiating with respect to dx, we get

F =  4GMm/4x^2-L^2.

To know more about gravitational force here

https://brainly.com/question/28691865

#SPJ4