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the potential difference across the terminals of a battery is 8.20 v when there is a current of 1.55 a in the battery from the negative to the positive terminal. when the current is 3.52 a in the reverse direction, the potential difference becomes 10.40 v.
potential difference across the terminals of a battery is 8.2
V when there is a current of 1.54A in the battery from the negative to the positive terminal. When the current is 3.49A in the reverse direction, the potential difference becomes 9.2V
A-What is the internal resistance of the battery?
B-What is the emf of the battery?

Respuesta :

The internal resistance of the battery is 0.1988 ohms and the emf of the battery is 8015 v

Given

V1=8.2 V

I1 =1.54 A

and

V2=9.2 V

I2=-3.49 A (since it is in reverse direction)

a)

since

E= V1+I1r

E=V2+I2r

V1+I1r =V2+I2r

8.2+1.54r =9.2-3.49r

5.03r =1

Resistance r=0.1988 ohms

b)

E=V1+I1r =8.2+1.54*0.1988

E=8.51 V

The effort required to transfer a unit of positive electric charge from one location to another is known as potential difference.  

Due to the potential difference between the two ends of the battery, if you connect the two ends of the same wire to the opposite ends of the same battery, electricity will flow through it.

Work is done by the component when electrons travel through it. The component receives a portion of the electrons' energy

Learn more about Resistance here:

https://brainly.com/question/29427458

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