Obtain The Deflection At The Mid-PointA horizontal beam is supported by a rigid pin at AA and a rod at CC. Both beam and rod are made of the same material, with elasticity modulus E=215 GPaE=215 GPa. The beam has moment of inertia I=58×106 mm4I=58×106 mm4 and the rod has cross-sectional area A=203 mm2A=203 mm2. Assume P=3 kNP=3 kN L=7 mL=7 m, and H=4 mH=4 m.By superposing the deflection of a simply supported beam and the deflection that a "rigid" beam would experience due to the stretching of the rod, determine the magnitude of the total deflection of point B. Assume small deformations and small rotations.

Respuesta :

The total deflection at the mid point b is B = 1.78786mm

How to calculate total deflection ?

M(x) divided by EI (Young's Modulus x Moment of Inertia) is the double integral of the Bending Moment Equation, which can be used to calculate deflection. where E is the young's modulous and I is the moment of inertia

M(x)/E * I

Beam deflection means the state of deformation of a beam from its original shape under the work of a force or load or weight. One of the most important applications of beam deflection is to obtain equations with which we can determine the accurate values of beam deflections in many practical cases.

Thus the total deflection is 1.78786mm

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