The spring in the figure (Figure 1)/ (a) is compressed by length delta x . It launches the block across a frictionless surface with speed v0. The two springs in the figure (Figure 2) (b) are identical to the spring of the figure (a). They are compressed by the same length delta x and used to launch the same block. What is the block's speed now?

Respuesta :

The speed from two springs is √2 times the speed with one spring.

The rate of change in position of an object in any course. Speed is measured because the ratio of distance to the time wherein the distance became included. Speed is a scalar amount because it has handiest route and no significance.

A quick-moving object has a high speed and covers a notably big distance in a given amount of time, whilst a sluggish-shifting item covers a relatively small amount of distance in the same amount of time.

The primary unit or the S.I. unit of speed is m/s or ms?¹.

Calculation :

The energy stored in the spring is 0.5*k*∆x²; this must equal the kinetic energy of the released block. 0.5*m*v0²:

0.5*m*v0² = 0.5*k*∆x²

v0 = ∆x*√[k/m]

Two springs will store twice the energy, so the stored energy in the two springs is k*∆x²

0.5*k*∆x² = k*∆x²

v0 = ∆x*√[2*k/m]

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