suppose baby kittens' weights are normally distributed with a mean of 12.3 and a standard deviation of 2.2. the z-score tells you how many units above the average (if z-score is positive) or below the average (if z-score is negative) any particular baby kitten's weight is. find the baby kitten weight that corresponds to the following z-scores given below. hint: use the formula x
X-μ Use the formula Z where is the mean, o is the standard deviation, and X is the baby kitten σ weight. a. Z= 1.98, X = b. Z-2.87, X =

Respuesta :

Using the formula X=μ+Zσ, the baby kitten's weight corresponds to the z-scores Z=1.98 and Z=2.87 are 16.656 and 18.614.

In a normal distribution, data points are referred to as x, whereas in a z distribution, they are referred to as z or z scores. A z score is a standard score that indicates how many standard deviations an individual statistic is from the mean (x). The formula used to calculate this z-score is Z= (X-μ)/σ where x is the raw score, σ is the population standard deviation, and μ is the population means. From this formula, X can be calculated as X=μ+Zσ.

For the first z-score, Z = 1.98, σ = 2.2 and μ = 12.3, then

X = 12.3+1.98(2.2) = 16.656

For the second z-score, Z = 2.87, σ = 2.2 and μ = 12.3, then

X = 12.3+2.87(2.2) = 18.614

The answers are 16.656 and 18.614.

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