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Algebra HELP PLS

The ceiling of Victoria's living room is a square that is 15√2 ft long on each side. To decorate for a party, she plans to hang crepe paper around the perimeter of the ceiling and then from each corner to the opposite corner. Victoria can buy rolls that each contain 30 ft of crepe paper. what is the minimum number of rolls she should buy?

pls show your work

Respuesta :

Answer:

The minimum number of rolls to buy is 9

Step-by-step explanation:

Find the perimeter of the ceiling of Katie’s living room

The perimeter of a square is equal to

P = 4b

b is the length side of the square

we have

b= 12ft

P = 4(12) = 48ft

Step 2

Find the length side of the diagonals  of the ceiling

Applying Pythagoras Theorem

[tex]d =\sqrt{12^{2} } +12^{2}[/tex]

[tex]d = \sqrt{288 = 16.97[/tex] ft

Step 3

Find the total crepe paper needed

Sum the perimeter plus two times the length side of the diagonal

[tex]48ft +2 * 16.97 ft[/tex]

Step 4

Find the number of rolls needed

we know that each roll contain 10 ft of crepe paper

so

81.94/10 = 81.9 rolls

Round Up

8.19 = 9 rolls

The minimum number of rolls to buy is 9

mhanifa

Answer:

  • Minimum 5 rolls

---------------------------------------

Total length we need is the sum of the perimeter and two diagonals of the square.

Perimeter:

  • P = 4s
  • P = 4(15√2) = 60√2 ≈ 85 ft (rounded up to the whole number)

Diagonals:

  • 2d = 2s√2 = 2(15√2)(√2) = 30*2 = 60 ft

Total length:

  • 85 + 60 = 145 ft

Number of rolls:

  • 145/30 ≈ 5 (rounded up to the whole number)

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