Answer:
(-1) & 4/3
Step-by-step explanation:
3x² - x - 4
Sum = -1
Product = 3*(-4) = -12
Factors = -4 and 3 { (-4)*3 = -12 & (-4) + 3 = -1}
3x² - x - 4 = 3x² + 3x - 4x -4 {Rewrite the middle term using the factors}
= 3x(x + 1) -4(x + 1)
=(x + 1)(3x - 4)
x + 1 = 0 ; 3x - 4 = 0
x = -1 ; 3x = 4
x = 4/3
[tex]\sf Zeroes \ of \ the \ polynomial \ are \ (-1) \ and \ \dfrac{4}{3}[/tex]
Verification:
[tex]\sf 3x^2 - x - 4 = 0\\\\Divide \ the \ entire \ equation \ by \ 3\\\\\\\dfrac{3x^2}{3}-\dfrac{x}{3}-\dfrac{4}{3}=0\\x^2 - \dfrac{x}{3}-\dfrac{4}{3}=0[/tex]
Coefficient of x = sum of the zeroes
[tex]\sf = -1 + \dfrac{4}{3}\\\\=\dfrac{-3}{3}+\dfrac{4}{3}\\\\=\dfrac{1}{3}\\\\[/tex]
Constant = product of the zeroes
[tex]\sf = (-1)*\dfrac{4}{3}\\\\=\dfrac{-4}{3}[/tex]
Thus verified.
